RefactorFlow

Same answer. Different process.

Developer A✓ 5/5
def is_palindrome(s):
    clean = s.lower()
    return clean == clean[::-1]

4 backspaces · 28s

Developer B✓ 5/5
def is_palindrome(s):
    if s == s[::-1]:
        return True
    clean = s.lower()
    return clean == clean[::-1]

47 backspaces · 4m 12s

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